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Cash needed to buy two normally priced jerseys

Question

Two football jerseys have random, independent prices: the first is normal with mean $80 and standard deviation $15, the second normal with mean $70 and standard deviation $20. Gabe wants a 97.5%97.5\% chance of being able to afford both. How many dollars should he carry? Take the standard normal's 9595th percentile to be 1.651.65 and its 97.597.5th percentile to be 1.961.96.

Short answer

$199. The total price is normal with mean 150150 and variance 152+202=62515^2+20^2=625, i.e. standard deviation 2525. Its 97.5%97.5\% quantile is 150+1.96⋅25=199150+1.96\cdot25=199.

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