Skip to content

Independence

"Are these two risks correlated?" is the single question that separates a diversified book from a concentrated one, and its cleanest possible answer is "no — they're independent." This note makes that word precise: independence is the special case of conditioning where learning that BB occurred changes nothing about AA's probability. The definition looks simple (P(A∩B)=P(A)P(B)\mathbb{P}(A\cap B)=\mathbb{P}(A)\mathbb{P}(B)), but the note exists because intuition about it is unreliable at every turn: disjoint events are never independent (a common first guess is exactly backwards), independence and conditional independence given a third event are logically unrelated, and — most consequentially for risk aggregation — pairwise independence of a collection of events does not imply their mutual independence. Every one of these traps is illustrated with a worked counterexample below, because in this topic the counterexample is the teaching content.
Learning objectives. By the end of this note you should be able to:
  • state the definition of independence of two events and derive its equivalence to P(A∣B)=P(A)\mathbb{P}(A\mid B)=\mathbb{P}(A);
  • explain why disjoint events with positive probability are never independent;
  • define conditional independence given an event CC, and produce an example where independence and conditional independence diverge;
  • define mutual independence of nn events and construct an example where pairwise independence holds but mutual independence fails;
  • compute success probabilities of series and parallel systems of independent components.

In this lesson

  1. Independence of two events
  2. Conditional independence
  3. Independence of a collection of events
  4. Series and parallel systems

Before you start

The full lesson, with worked examples and exercise solutions, is for members.

Read the full lesson

New to SelfMadeQuant.com? See membership options or browse the Probability, Statistics and Financial Data syllabus.