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Maximum of four Unif(0,4) draws in (2,3]

Question

Four independent random variables are each uniform on (0,4)(0,4). What is the probability that the largest of them lies in (2,3](2,3]?

Short answer

65/25665/256. The maximum is at most xx exactly when all four are, with probability (x/4)4(x/4)^4. So the answer is (3/4)4−(2/4)4=81−16256(3/4)^4-(2/4)^4=\tfrac{81-16}{256}.

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