Skip to content

Law of the time integral of Brownian motion

Question

Let ww be a standard Brownian motion. What is the distribution of the random variable ∫0Tw(t) dt\int_0^T w(t)\,dt?

Short answer

Normal with mean 00 and variance T3/3T^3/3. It is a limit of linear combinations of Gaussians, so it is Gaussian with mean 00. Its variance is ∫0T∫0Tmin⁡(s,t) ds dt=T3/3\int_0^T\int_0^T\min(s,t)\,ds\,dt=T^3/3. Equivalently, integrating by parts gives ∫0T(T−t) dw(t)\int_0^T(T-t)\,dw(t), whose Ito-isometry variance is again T3/3T^3/3.

Adapted from Crack, Heard on the Street, Q2.29, p.28; question and answer rewritten by SelfMadeQuant.com.

See the hint and the full worked solution in the question bank (free account).

Open the worked solution

Lessons behind this question

Start with a free lesson: Expectation, Variance and Covariance is part of a free topic. Create a free account, no card needed, to read it in full with worked solutions.

Read it free