Pooled t-test p-value for weekend versus weekday spending

A researcher samples $20$ weekend shoppers (mean spend $78, standard deviation $22) and, independently, $20$ weekday shoppers (mean $67, standard deviation $20). Assuming normal spending with equal variances, find the two-sided p-value for testing whether the mean spends differ, to three significant figures.

$0.106$. The pooled standard deviation is $\sqrt{(22^2+20^2)/2}\approx21.02$, so $t=\dfrac{11}{21.02\sqrt{0.1}}\approx1.655$ on $38$ degrees of freedom. Doubling the upper tail gives about $0.106$, not significant at $5\%$.