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Fixed-payout binary call and its link to vanillas

Question

A European binary option pays a fixed cash amount AA at TT if ST>XS_T > X and nothing otherwise. Under Black-Scholes, what is it worth, and how does it relate to the price of an ordinary call?

Short answer

Ae−rTN(d2)A e^{-rT} N(d_2). It is the discounted risk-neutral probability of finishing above XX, times AA. Since ∂C/∂X=−e−rTN(d2)\partial C/\partial X = -e^{-rT}N(d_2), the binary equals −A ∂C/∂X-A\,\partial C/\partial X: it is the limit of a tight call spread, long A/εA/\varepsilon calls at X−εX - \varepsilon and short A/εA/\varepsilon at XX.

Adapted from Crack, Heard on the Street, Q2.10, p.24; question and answer rewritten by SelfMadeQuant.com.

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