Three people all stopping within two tosses

Each of three people tosses a coin that lands heads with probability $0.25$, stopping at their first tails. What is the probability that nobody needs more than two tosses?

$3375/4096$. One person finishes within two tosses unless the first two are both heads, so the chance is $1-\tfrac{1}{16}=\tfrac{15}{16}$. By independence the answer is $(15/16)^3=3375/4096$.