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Expected ratio of partial sums S40 over S20

Question

Take i.i.d. random variables X1,…,X40X_1,\dots,X_{40} with mean E[X1]=2\mathbb{E}[X_1]=2, and set Sn=X1+⋯+XnS_n=X_1+\cdots+X_n. You are told that E[1/S20]=110\mathbb{E}[1/S_{20}]=\tfrac{1}{10}. Find E[S40/S20]\mathbb{E}[S_{40}/S_{20}].

Short answer

55. Write S40/S20=1+∑i=2140Xi/S20S_{40}/S_{20}=1+\sum_{i=21}^{40}X_i/S_{20}. Each XiX_i with i>20i>20 is independent of S20S_{20}, so each term has expectation 2⋅1102\cdot\tfrac{1}{10}, giving 1+20⋅0.2=51+20\cdot0.2=5.

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