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Ratio of all Fibonacci terms to every third one

Question

With F1=F2=1F_1=F_2=1 and Fn+1=Fn+Fn−1F_{n+1}=F_n+F_{n-1}, evaluate the ratio ∑i=1300Fi∑j=1100F3j.\frac{\sum_{i=1}^{300}F_i}{\sum_{j=1}^{100}F_{3j}}.

Short answer

22. Group the numerator in triples: F3k−2+F3k−1+F3k=F3k+F3k=2F3kF_{3k-2}+F_{3k-1}+F_{3k}=F_{3k}+F_{3k}=2F_{3k}. So the numerator is exactly twice the denominator.

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