Skip to content

Measuring 45 seconds with two irregular fuses

Question

You have two fuses, each of which takes exactly one minute to burn end to end, but they burn unevenly so length tells you nothing about time. How can you time exactly 4545 seconds?

Short answer

Light fuse A at both ends and fuse B at one end together. A burns out after 3030 seconds; at that moment light B's other end. B's remaining 3030 seconds of burn now goes twice as fast and ends 1515 seconds later, at 4545 seconds.

Adapted from Crack, Heard on the Street, Q1.52, p.19; question and answer rewritten by SelfMadeQuant.com.

See the hint and the full worked solution in the question bank (free account).

Open the worked solution

Lessons behind this question

Start with a free lesson: Probability Fundamentals is part of a free topic. Create a free account, no card needed, to read it in full with worked solutions.

Read it free