Finishing position from distances to last and halfway

In a race, a driver finished $14$ positions ahead of last place and $6$ positions behind the last spot of the top half of the field. What position did he finish in?

$26$th. If he is in place $x$, the field has $x+14$ drivers and the top half ends at place $x-6$. Setting $x-6=\tfrac{x+14}{2}$ gives $x=26$ (a field of $40$).