The previous lesson stated the Neyman-Fisher factorization theorem — is sufficient for if and only if — and used it as a computational black box to find sufficient statistics for five different families without ever proving the "if and only if." This note supplies the missing proof in the discrete case, where it reduces to two short conditional-probability computations, one in each direction. It closes with a remark on what changes (and what doesn't) when the theorem is extended to continuous families.
Learning objectives. By the end of this note you should be able to:
- reproduce the proof that factorization implies sufficiency, by computing the conditional pmf of given directly;
- reproduce the proof that sufficiency implies factorization, by writing as a product of the marginal pmf of and a conditional term;
- identify exactly where each direction of the proof uses the definitions of sufficiency and factorization;
- state what additional machinery the continuous (dominated-family) version of the theorem requires, without needing to execute it in full generality.
In this lesson
- Setup
- Factorization implies sufficiency
- Sufficiency implies factorization
- Extension to continuous families
Before you start
- Sufficient Statistics and the Neyman-Fisher Factorization Theorem
- Joint PMFs of Multiple Random Variables
- Conditional Probability, Total Probability, and Bayes' Rule
The full lesson, with worked examples and exercise solutions, is for members.
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