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Calculus II: Vector Calculus and Multivariable Analysis / Multivariable Differential Calculus

Derivation — The Gradient as the Direction of Steepest Ascent

The claim that "the gradient points in the direction of steepest ascent" is not just a slogan — it has a clean proof using the Cauchy-Schwarz inequality. Similarly, the fact that "the gradient is perpendicular to level curves" follows from a one-line chain-rule argument. Both proofs are short but non-obvious the first time; understanding them makes the gradient intuition durable rather than memorised.

Learning objectives. By the end of this note you should be able to:
  • prove that DufD_\mathbf{u} f is maximised when u=∇f/∥∇f∥\mathbf{u} = \nabla f/\|\nabla f\| using Cauchy-Schwarz;
  • prove that ∇f\nabla f is perpendicular to the level curve {f=c}\{f = c\} at any point via the chain rule;
  • interpret the shadow price λ\lambda in Lagrange multipliers as the rate of change of the optimum with respect to the constraint — the financial interpretation of the gradient perpendicularity condition.

In this lesson

    1. Proof: The Gradient Is the Steepest Ascent Direction
    1. Proof: The Gradient Is Perpendicular to Level Curves
    1. The Lagrange Condition from Gradient Perpendicularity
    1. Directional Derivative at a Critical Point

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