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Intuition behind the Ito correction term

Question

Explain why Ito's lemma takes the form it does.

Short answer

Taylor expansion where the second-order term survives. Expanding f(t,X)f(t,X) gives ft dt+fx dX+12fxx(dX)2+…f_t\,dt+f_x\,dX+\tfrac12f_{xx}(dX)^2+\dots. In ordinary calculus (dX)2(dX)^2 is negligible, but for dX=μ dt+σ dWdX=\mu\,dt+\sigma\,dW the increment dWdW is of size dt\sqrt{dt}, so (dX)2=σ2dt(dX)^2=\sigma^2dt is first order. Higher terms vanish, leaving df=(ft+μfx+12σ2fxx)dt+σfx dWdf=(f_t+\mu f_x+\tfrac12\sigma^2f_{xx})dt+\sigma f_x\,dW; convexity of ff creates a drift.

Adapted from Joshi, Denson & Downes, Quant Job Interview Questions and Answers, Q3.54, p.85; question and answer rewritten by SelfMadeQuant.com.

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