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z statistic for 36 salespeople averaging 17 deals

Question

A manager believes his team closes at most 1515 deals per person per week on average. He samples 3636 salespeople in one week and finds a sample mean of 1717 deals and a sample variance of 99. He tests whether the true mean exceeds 1515. Assuming random sampling and roughly normal counts, what is the value of his test statistic?

Short answer

44. With n=36n=36 a z statistic is appropriate: z=17−153/36=20.5=4z=\dfrac{17-15}{3/\sqrt{36}}=\dfrac{2}{0.5}=4.

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