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Probability a sample mean of 25 reaches 165

Question

Draw 2525 independent observations from a normal population with mean 160160 and variance 900900. Find, to four decimal places, the probability that their average is at least 165165.

Short answer

0.20230.2023. The sample mean is normal with mean 160160 and standard deviation 30/25=630/\sqrt{25}=6, so the probability is P(Z≥5/6)≈0.2023\mathbb{P}(Z\ge 5/6)\approx0.2023.

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