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Expected minimum of three 100-sided dice

Question

Three fair dice, each numbered 11 to 100100, are rolled. What is the expected value of the smallest number showing?

Short answer

25.502525.5025. Sum the tail probabilities: P(min⁡≥k)=(101−k100)3\mathbb{P}(\min\ge k)=\left(\tfrac{101-k}{100}\right)^3, so the expectation is 11003∑j=1100j3=50502106=25.5025\tfrac{1}{100^3}\sum_{j=1}^{100}j^3=\tfrac{5050^2}{10^6}=25.5025.

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