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When the snow began, from a plough's progress

Question

Snow has been falling at a steady rate since some time before noon. At noon a snowplough sets off; it clears a fixed volume of snow per minute, so its speed is inversely proportional to the snow depth. It covers 22 miles between noon and 1 pm and 11 mile between 1 pm and 2 pm. At what time did the snow start?

Short answer

About 11:23 am (T=5−12≈0.618T=\tfrac{\sqrt5-1}{2}\approx0.618 h before noon). Depth is proportional to t+Tt+T, so speed is c/(t+T)c/(t+T) and distances are cln⁡T+1T=2c\ln\frac{T+1}{T}=2 and cln⁡T+2T+1=1c\ln\frac{T+2}{T+1}=1. Hence T+1T=(T+2T+1)2\frac{T+1}{T}=\left(\frac{T+2}{T+1}\right)^2, which simplifies to T2+T−1=0T^2+T-1=0.

Adapted from Zhou, A Practical Guide to Quantitative Finance Interviews, sec. 3.2 Integration, 'Applications of integration B', p.38; question and answer rewritten by SelfMadeQuant.com.

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