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Upward-biased walk ever reaching +1

Question

A particle begins at 00 and moves along the integers in steps of size one: each step is upward with probability p=23p=\tfrac23 and downward otherwise, independently. What is the probability that the particle eventually visits position 11?

Short answer

11. Let hh be the probability of ever climbing one level. A first step up succeeds; a first step down requires climbing two levels, so h=p+(1−p)h2h=p+(1-p)h^2, with roots 11 and p/(1−p)=2p/(1-p)=2. Since h≤1h\le1, h=1h=1: a walk with upward drift reaches +1+1 almost surely.

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