Two red then two blue jellybeans

A bag has $6$ red and $10$ blue jellybeans. A child pulls out four of them, one at a time and at random, without putting any back. What is the chance that the first two are red and the last two are blue?

$45/728$. Multiply the sequential probabilities: $\tfrac{6}{16}\cdot\tfrac{5}{15}\cdot\tfrac{10}{14}\cdot\tfrac{9}{13}=\tfrac{2700}{43680}=\tfrac{45}{728}$.