Fair price of a repeated two-tetrahedron game

Each turn you roll two four-sided dice, one red and one blue, each numbered 1 to 4. If blue beats red you receive the difference; if red beats blue you receive nothing. If they tie, the game ends at once; otherwise you play another turn. What is the fair value of this game?

$2.5$. Per turn, $P(\text{tie})=\tfrac14$ and the expected payment is $\tfrac{1}{16}(3\cdot1+2\cdot2+1\cdot3)=\tfrac58$. The value satisfies $V=\tfrac58+\tfrac34V$, so $V=\tfrac52$.