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Fair die plus a value-weighted die: odd total

Question

Emma throws two six-sided dice numbered 11 to 66. The first is fair. The second is biased so that the chance of each face is proportional to the number on it. What is the probability that the two numbers add to an odd total?

Short answer

1/21/2. An odd sum needs exactly one die to be odd. Because the fair die is odd or even with probability 12\tfrac12 each, P(odd sum)=12P(biased odd)+12P(biased even)=12P(\text{odd sum}) = \tfrac12 P(\text{biased odd}) + \tfrac12 P(\text{biased even}) = \tfrac12, whatever the bias.

Adapted from QuantQuestions.io; question and answer rewritten by SelfMadeQuant.com.

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