Each of four players dealt exactly one ace

A well-shuffled $52$-card deck is dealt out completely to four players, $13$ cards each. What is the probability that every player ends up holding exactly one ace?

$2197/20825\approx0.1055$. Place the aces one at a time into the $52$ slots: the second ace must avoid the first ace's hand ($39/51$), the third must avoid two hands ($26/50$), and the fourth three hands ($13/49$). The product is $\tfrac{39\cdot26\cdot13}{51\cdot50\cdot49}$.