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Average card value when hearts count double

Question

Give each card in a standard 52-card deck its rank as a value (ace =1=1, numbers at face value, jack =11=11, queen =12=12, king =13=13), except that every heart is worth twice its rank (so the ace of hearts is worth 22). If one card is drawn uniformly at random, what is its expected value?

Short answer

354\tfrac{35}{4}. Each suit's ranks sum to 9191, and hearts count twice, so the deck totals 5×91=4555\times 91=455. Dividing by 5252 cards gives 8.758.75.

Adapted from QuantQuestions.io; question and answer rewritten by SelfMadeQuant.com.

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