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Two-step tree value of a squared-stock payoff

Question

A stock starts at 55 and in each of two periods either doubles or halves, with zero interest. A contract pays S22S_2^2 at the end of the second period. Using risk-neutral pricing on the binomial tree, what is it worth today?

Short answer

56.2556.25. The risk-neutral up probability solves 2q+12(1−q)=12q+\tfrac12(1-q)=1, giving q=13q=\tfrac13. Terminal prices 20,5,1.2520,5,1.25 occur with probabilities 19,49,49\tfrac19,\tfrac49,\tfrac49, so the value is (400+4⋅25+4⋅1.5625)/9=56.25(400+4\cdot25+4\cdot1.5625)/9=56.25.

Adapted from QuantQuestions.io; question and answer rewritten by SelfMadeQuant.com.

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