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Option value recovered from its Greeks

Question

A pricing system is offline, but you still have these figures for an option on a stock:

  • theta Θ=−1.9\Theta = -1.9
  • delta Δ=0.3\Delta = 0.3
  • gamma Γ=0.03\Gamma = 0.03
  • risk-free rate r=0.03r = 0.03
  • variance σ2=0.2\sigma^2 = 0.2
  • stock price S=25S = 25

Assuming Black-Scholes, what is the option worth, to two decimal places?

Short answer

6.676.67. Any Black-Scholes price satisfies Θ+12σ2S2Γ+rSΔ=rV\Theta + \tfrac12\sigma^2S^2\Gamma + rS\Delta = rV. Here −1.9+1.875+0.225=0.2-1.9 + 1.875 + 0.225 = 0.2, so V=0.2/0.03≈6.67V = 0.2/0.03 \approx 6.67. The trick fails when r=0r=0, since VV then drops out of the equation.

Adapted from QuantQuestions.io; question and answer rewritten by SelfMadeQuant.com.

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