Skip to content

One-step three-branch tree for an at-the-money call

Question

A stock starts at S0=8S_0 = 8. Over one period it moves to one of three levels: up 30%30\% with probability 0.20.2, unchanged with probability 0.50.5, or down 50%50\% with probability 0.30.3. Treat these as the pricing probabilities and ignore discounting. What is today's value of a European call struck at K=8K = 8 that expires at the end of the period?

Short answer

0.480.48. The terminal prices are 10.410.4, 88 and 44; only the up state pays, giving 10.4−8=2.410.4 - 8 = 2.4. Weighting by its probability gives 0.2×2.4=0.480.2 \times 2.4 = 0.48. (A trinomial tree is incomplete, which is why the probabilities have to be supplied rather than derived.)

Adapted from QuantQuestions.io; question and answer rewritten by SelfMadeQuant.com.

See the hint and the full worked solution in the question bank (free account).

Open the worked solution

Lessons behind this question

Start with a free lesson: Options is part of a free topic. Create a free account, no card needed, to read it in full with worked solutions.

Read it free