Turning down one or two adjacent cards in a row of ten

Ten cards lie face up in a line. Two players alternate turns. On the very first move, the first player must turn exactly one card face down. Thereafter, on each turn a player turns face down either one face-up card or two face-up cards that are next to each other. The player who turns down the final card wins. With best play, who wins? Answer $1$ for the first player, $2$ for the second.

$1$ (the first player). For instance, turning down the third card from an end splits the row into piles of $2$ and $7$; this is the game Kayles and the Sprague-Grundy values of these piles cancel ($G(2)=G(7)=2$), so the first player can keep returning a zero position, e.g. by mirroring across symmetric sub-rows, and takes the last card.