Survivor when every second person in a circle of 100 falls

One hundred people stand in a circle labelled $1$ to $100$. Person $1$ eliminates person $2$ and hands the sword to person $3$, who eliminates person $4$, and so on around the circle, each surviving holder removing the next living person. Who is the last person left?

Person 73. This is the Josephus problem with step 2. Write $n=2^m+\ell$ with $2^m$ the largest power of two not above $n$; the survivor is $2\ell+1$. Here $100=64+36$, giving $73$.