Race to call 50 adding one to ten each turn

Bob and Jill alternately call out numbers, and whoever calls $50$ wins. The opening call must be an integer from $1$ to $10$, and every later call must exceed the previous call by at least $1$ and at most $10$. With perfect play on both sides, does Bob want to make the first call?

Yes. Work backwards: whoever calls $50$ wins, so calling $39$ wins (the opponent must then say something in $40$–$49$), and likewise $28$, $17$ and $6$ are winning calls, each $11$ apart. Bob should open with $6$ and then always answer with the next number in $17, 28, 39, 50$.