Next calendar date with eight different digits

Writing dates as $MM/DD/YYYY$, find the earliest date from today (the $2020$s) onward in which all eight digits are different (e.g. $01/23/4567$ would qualify). Give it as $MMDDYYYY$.

$06172345$ (June 17, 2345). The year must start with $2$, so the month and day cannot use $2$. A month is $0x$ or $10$, and a valid day then needs a leading $1$ or a $0$, so $0$ and $1$ are always used by $MMDD$. The earliest year is therefore $2345$, and from the leftover digits $0,1,6,7,8,9$ the earliest date is $06/17$.