Latest past date with eight different digits

Writing dates as $MM/DD/YYYY$, find the most recent date (up to today) in which all eight digits are different, such as $01/23/4567$ would be if it were in the past. Give it as $MMDDYYYY$.

$06251987$. A year beginning with $2$ leaves no valid month-day combination without repeating $0$, $1$ or $2$, so the year starts with $1$ and the month with $0$. Maximising the rest gives year $1987$, then month $06$ and day $25$; a scan of all dates confirms it.