Closest factor pair of 1234567890

Among all ways of writing $1234567890 = a \cdot b$ with $a, b$ positive integers, choose the pair whose difference $|a-b|$ is as small as possible. What is $a+b$ for that pair? (Factoring the number into primes will help.)

70297. Since $1234567890 = 2\cdot 3^2\cdot 5\cdot 3607\cdot 3803$, the two large primes must sit in different factors (both together already exceed $\sqrt{N}\approx 35136$). Distributing the small part $90$ to balance them gives $3607\cdot 10=36070$ and $3803\cdot 9=34227$, the nearest pair, with sum $70297$.