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Replacing urn balls with blue until all blue

Question

An urn holds 2 red balls and 1 blue ball. Each step you draw a ball uniformly at random and put back a blue ball in its place, whatever colour you drew. What is the expected number of draws until every ball in the urn is blue?

Short answer

9/29/2. With 2 reds the next draw is red with probability 23\tfrac23 (mean wait 32\tfrac32 draws); with 1 red it is 13\tfrac13 (mean wait 3). The two geometric waits add to 32+3=92\tfrac32+3=\tfrac92.

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